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Problem 13-4 Suppose the inductive reactance in an RL circuit is 680 and the resistance is 840 What is the phase angle The ratio XL/R is 680/840 A calculator will display this quotient as something like 08095 and some more digits Find the arctangent of this number You should get 3899 and some more digits This can be rounded off to 390 Problem 13-5 Suppose an RL circuit operates at a frequency of 10 MHz with a resistance of 10 and an inductance of 90 H What is the phase angle What does this tell us about the nature of this RL circuit at this frequency Find the inductive reactance using the formula XL = 628fL = 628 10 90 = 565 Then find the ratio XL/R = 565/10 = 565 The phase angle is equal to arctan 565, which, rounded to two

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One of the most common newbie questions is how to remove duplicate data from a table. After demonstrating the requisite query to remove the duplicated data (removing what might actually be a row of important data that the user updated instead of the kept copy), a nice but stern rant follows on why you must protect your data against duplicated data. In SQL Server, uniqueness is enforced using either a primary key or a unique constraint. The primary key is used for the main value that each row will be referenced as. Unique constraints are then applied to all other candidate keys, which are frequently other sets of columns that a user will want to reference a row as. Every table should have a primary key to make sure that you have some way to distinguish one row from other rows. In addition, it s important to make sure that you have either the primary key or a unique key on a value in the table that has some meaning. An identity value in the table doesn t have any actual meaning, as you could have two rows with exactly the same value other than the identity key, and the two rows would be technically indistinguishable from one another. This isn t always completely

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One particular operation isn t present in table 2: delete, the removal of entities from the database, won t be supported by our solution. Before continuing, please take another good look at the tables.

The source system s ASM diskgroups must be configured with normal or high redundancy Application impact can be controlled such that the rebalance happens with minimal impact This can be adjusted with the POWER clause of the rebalance operation Since ASM on Exadata needs to access the legacy storage, the legacy storage must be exposed to the Database Machine using NFS or iSCSI If moving from a previous version of the Database Machine, then you should connect the two machines using the InfiniBand Network or the 10 Gigabit Ethernet Although the migration itself will incur zero downtime, in reality, there will be a slight downtime incurred in order to switch the database and ASM instances from the non-Exadata platform to the Database Machine

sistors can demand more than 1000 W (1 kW ) in some cases At 12 V, this translates to a current demand of 90 A or more Television sets have cathode-ray tubes that need several hundred volts This is derived by using a step-up transformer in the power supply Such transformers don t have to supply a lot of current, though, so they are not very big or heavy Another type of device that needs rather high voltage is a ham-radio amplifier with vacuum tubes Such an amplifier requires from 2 kV to 5 kV Any voltage higher than about 12 V should be treated with respect Warning: The voltages in televisions and ham radios can present an electrocution hazard, even after the equipment has been switched off Do not try to service such equipment unless you are trained to do so!

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