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The source of the Band data is an XML entity based on the Band XML Schema shown in listing 2 earlier in this chapter. This XML Schema provides all the data for the Band and Person entities, including the data for the Band Member associative entity. Compare the XML namespace declarations in listing 10 with the declaration in the code listings presented earlier. Is there something different Why

Open Dictionary dialog box (see Figure 3-5)

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Calculating EAN-8 / EAN-13 check digits with C# . The following two code snippets show how to create an EAN8 / EAN13 check digit . Both routines also test the ...
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xmlnamespaces ( 'http://www.w3.org/2001/XMLSchema-instance' as xsi ,'http://schemas.milambda.net/Music' as m ,'http://schemas.milambda.net/Music-Band' as mb ) distinct Bands.Band.query (' data(@mb:bandName) ').value ( '.' ,'nvarchar(450)' ) as [Name] ,nullif(Bands.Band.query (' data(@mb:established) ').value ( '.' ,'datetime' ), N'') as Established ,nullif(Bands.Band.query (' data(@mb:disbanded) ').value ( '.' ,'datetime' ), cast(N'99991231' as datetime)) as Disbanded from @xml.nodes (' /mb:bands/mb:band ') Bands (Band)

Problem 14-1 Suppose a capacitor has a value of 000100 F at a frequency of 100 MHz What is the capacitive reactance

Figure 3-5

xmlnamespaces ( 'http://www.w3.org/2001/XMLSchema-instance' as xsi ,'http://schemas.milambda.net/Music' as m ,'http://schemas.milambda.net/Music-Band' as mb ) distinct Bands.Band.query (' data(@mb:bandName) ').value ( '.'

,'nvarchar(450)' ) as [Name] ,nullif(Bands.Band.query (' data(@mb:established) ').value ( '.' ,'datetime' ), N'') as Established ,nullif(Bands.Band.query (' data(@mb:disbanded) ').value ( '.' ,'datetime' ), N'') as Disbanded from @xml.nodes (' /mb:bands/mb:band ') Bands (Band)

is negatively, and inversely, proportional to capacitance Capacitive reactance is also negatively, and inversely, proportional to frequency

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In the Open Dictionary dialog box, either pick the application from the list or click the Browse button to locate it elsewhere

By combining the queries listed previously into a workflow of data management operations, we can design two SQL procedures, each with a specific purpose based on the two principal business entities mentioned in the section The XML Schema : one procedure to save the Album data and one procedure to save the Band data.

Here s a beginner s trick for memorizing XML retrieval methods: Nodes provide the set, query retrieves the data element, and value extracts the data.

If you find two or more listings for the application, choose the one with the highest version number (in the Version column) If two or more versions have the same number, pick the one in your Applications folder over any others

Use the formula and plug in the numbers You can do this directly, because the data is specified in microfarads (millionths) and in megahertz (millions): X C = 1/(628 10 000100) = 1/(000628) = 159 This is rounded to three significant figures, because all the data is given to that many digits

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We haven t discussed one important issue yet the question of associative entities. As you may have observed in our examples, only the primary entities are listed. Why is that The answer is simple: associative entities, representing the many-to-many relationships between the primary entities, can be retrieved from the XML source by combining the queries used in retrieving the data of the individual primary entities of a particular relationship. The combinations are listed in table 5.

file opens in a AppleScript Editor window that bears the application s name, so you can easily see which dictionary it is (see Figure 3-6)

Table 5 Retrieving the associative entities Provided by combining these primary entities Track joined with Person based on the nesting of the Author XML element inside the Track XML element of the Album XML Track joined with Band based on the nesting of the Band XML element inside the Track XML element of the Album XML Band joined with Person based on the nesting of the Person XML element inside the Band XML element of the Band XML

Problem 14-2 What is the capacitive reactance of the preceding capacitor if the frequency decreases to zero (that is, if the voltage source is pure dc) In this case, if you plug the numbers into the formula, you get a zero denominator Mathematicians will tell you that such a quantity is undefined But we can say that the reactance is negative infinity for all practical purposes Problem 14-3 Suppose a capacitor has a reactance of 100 at a frequency of 100 MHz What is its capacitance In this problem, you need to put the numbers in the formula and solve for the unknown C Begin with this equation:

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A detailed tutorial with C# sample code is provided for users. When using the sample code to generate UPC -A barcode images, users need to download our free ...

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