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three_d three_d::operator=(three_d t) { x = tx; y = ty; z = tz; return *this; } // Show X, Y, Z coordinates void three_d::show() { cout << x << ", "; cout << y << ", "; cout << z << "\n"; } // Assign coordinates void three_d::assign(int mx, int my, int mz) { x = mx; y = my; z = mz; } int main() { three_d a, b, c; aassign(1, 2, 3); bassign(10, 10, 10); ashow(); bshow(); c = a+b; // now add a and b together cshow(); c = a+b+c; // add a, b and c together cshow(); c = b = a; cshow(); // demonstrate multiple assignment

Did you turn off the water before installation Were there any leaks Did you turn the water back on Did you configure the connections properly for normally open or

22:

bshow(); return 0; }

This program produces the following output:

11

1, 2, 3 10, 10, 10 11, 12, 13 22, 24, 26 1, 2, 3 1, 2, 3

As you examine this program, you may be surprised to see that both operator functions have only one parameter each, even though they overload binary operations This is because, when a binary operator is overloaded using a member function, only one argument is explicitly passed to it The other argument is implicitly passed using the this pointer Thus, in the line

C++ tempx = x + tx;

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the x refers to this >x, which is the x associated with the object that invoked the operator function In all cases, it is the object on the left side of an operation that causes the call to the operator function The object on the right side is passed to the function In general, when using a member function, no parameters are needed when overloading a unary operator, and only one parameter is required when overloading a binary operator (You cannot overload the ternary operator) In either case, the object that causes the activation of the operator function is implicitly passed through the this pointer To understand how operator overloading works, let s examine the preceding program carefully, beginning with the overloaded operator + When two objects of type three_d are operated on by the + operator, the magnitudes of their respective coordinates are added together, as shown in the operator+( ) function associated with this class Notice, however, that this function does not modify the value of either operand Instead, an object of type three_d, which contains the result of the operation, is returned by the function To understand why the + operation does not change the contents of either object, think about the standard arithmetic + operation as applied like this: 10+12 The outcome of this operation is 22, but neither 10 nor 12 is changed by it Although there is no rule that states that an overloaded operator cannot alter the value of one of its operands, it usually makes sense for the overloaded operator to stay

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